FIND THE SUM OF ALL NUMBERS GREATER THAN 10,000 FORMED BY USING THE DIGITS 0,2,4,6,8 NO DIGIT BEING REPEATED IN ANY NUMBER.

Dear shaurya

Let 2 at first position

    rest 4 position can be filled by 4*4*4*4=256 ways

  every digit from 0,4,6,8 come at unit place 256/4 =64 times

 

 so some of all the digit at unit place = 64*(0+4+6+8)

each of 0,4,5,8 digit also occur at 64 times 10th hundred and thousand place

so sum of digit =64(0+4+6+8)(1+10+100+1000)   + 2 * 10000

similarly for the other digit

4 at first place sum =64(0+2+6+8)(1+10+100+1000)   + 4 * 10000

6 at first place sum =64(0+2+4+8)(1+10+100+1000)   + 6 * 10000

8 at first place sum =64(0+2+6+4)(1+10+100+1000)   + 8 * 10000

 

so total sum  =64(2+6+4+8)*3*(1+10+100+1000)   + (2+4+6+8) * 10000

             solve it this will be your final result

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